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A tangent to the ellipes x^2/25+y^2/16=1...

A tangent to the ellipes `x^2/25+y^2/16=1` at any points meet the line `x=0` at a point Q Let R be the image of Q in the line `y=x,` then circle whose extremities of a dameter are `Q and R` passes through a fixed point, the fixed point is

A

(3,0)

B

(4,0)

C

(5,0)

D

(0,0)

Text Solution

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The correct Answer is:
D
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