Home
Class 12
MATHS
The graph of the conic x^(2)-(y-1)^(2)=1...

The graph of the conic `x^(2)-(y-1)^(2)=1` has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b).
Q. Length of the latusrectum of the conic is

A

`1`

B

`sqrt(2)`

C

`2`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • HYPERBOLA

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|10 Videos

  • HYPERBOLA

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|8 Videos

  • HYPERBOLA

    ARIHANT MATHS|Exercise Exercise (More Than One Correct Option Type Questions)|15 Videos

  • GRAPHICAL TRANSFORMATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|10 Videos

  • INDEFINITE INTEGRAL

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|8 Videos

Similar Questions

Explore conceptually related problems

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Q. If e be the eccentricity of the conic, then the value of (1+e^(2)+e^(4)) is

the graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin.The point of the tangency being (a,b) then find the value of sin^(-1)((a)/(b))

If the slope of a line that passes through the origin which is tangent to y= x^(3) + x + 54 is m, then m is equal to

If a line with positive slope passing through point P(0,1) interesects the curve y=x^(2)-x at A and B such that PA.PA=2, then AB is:

A circle passes through origin and touches the line y=x+2 with one of its diameters being y=x+1 ,then the centre of the circle

The slope of the line passing through the points (a^(2),b)and (b^(2),a) is

The slopes of the line which passes through the origin, and the mid - point of the line segment joining the points. P(3, -4) and Q(-5, -2) is

Find the equation of the cure which passes through the origin and has the slope x+3y-1 at the point (x,y) on it.

Graph the line passing through the point P and having slope m. P=(1,2),m=2