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Prove that : sintheta/cos[3theta]+sin[...

Prove that : `sintheta/cos[3theta]+sin[3theta]/cos[9theta]+sin[9theta]/cos[27theta]=1/2[tan[27theta]-tan[theta]]`

A

`1/2 log |(sec 27 theta)/(sec theta)|+C`

B

`1/2 log |(sec theta)/(sec 27 theta)|+C`

C

`1/2 log |root(2)(sec 27 theta)/(sec theta)|+C`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
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