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Statement I int((1)/(1+x^(4)))dx=tan^(-1...

Statement I `int((1)/(1+x^(4)))dx=tan^(-1)(x^(2))+C`
Statement II `int(1)/(1+x^(2))dx=tan^(-1)x +C`

A

Statement I is true, Statement II is also true , Statement II is the correct explanation of Statement I.

B

Statement I is true, Statement II is also true, Statement II is not the correct explanation of Statement I.

C

Statement I is true, Statement II is false.

D

Statement I is false, Statement II is true .

Text Solution

AI Generated Solution

The correct Answer is:
To determine the validity of the two statements regarding indefinite integrals, we will analyze each statement step by step. ### Statement I: \[ \int \frac{1}{1+x^4} \, dx = \tan^{-1}(x^2) + C \] **Step 1: Analyze the Integral** The integral \(\int \frac{1}{1+x^4} \, dx\) does not have a straightforward antiderivative. We need to manipulate it to find a solution. **Step 2: Factor the Denominator** We can factor \(1 + x^4\) as: \[ 1 + x^4 = (x^2 + \sqrt{2}x + 1)(x^2 - \sqrt{2}x + 1) \] This allows us to use partial fraction decomposition. **Step 3: Set Up Partial Fraction Decomposition** We express: \[ \frac{1}{1+x^4} = \frac{A}{x^2 + \sqrt{2}x + 1} + \frac{B}{x^2 - \sqrt{2}x + 1} \] Multiplying through by the denominator gives: \[ 1 = A(x^2 - \sqrt{2}x + 1) + B(x^2 + \sqrt{2}x + 1) \] **Step 4: Solve for Coefficients A and B** Expanding and equating coefficients, we can find values for \(A\) and \(B\). This will involve solving a system of equations. **Step 5: Integrate Each Term** Once we have \(A\) and \(B\), we can integrate each term separately. The integrals will involve arctangent functions. **Step 6: Conclusion for Statement I** After performing the integration, we find that the result does not simplify to \(\tan^{-1}(x^2) + C\). Therefore, **Statement I is false**. ### Statement II: \[ \int \frac{1}{1+x^2} \, dx = \tan^{-1}(x) + C \] **Step 1: Analyze the Integral** The integral \(\int \frac{1}{1+x^2} \, dx\) is a standard integral. **Step 2: Recognize the Standard Result** The integral \(\int \frac{1}{1+x^2} \, dx\) is known to equal \(\tan^{-1}(x) + C\). **Step 3: Conclusion for Statement II** Since this is a well-known result, **Statement II is true**. ### Final Conclusion: - **Statement I is false.** - **Statement II is true.**
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