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If x*a=0, x*b=1, [x a b]=1 and a*b ne 0,...

If `x*a=0, x*b=1,` [x a b]=1 and `a*b ne 0`, then find x in terms of a and b.

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The correct Answer is:
`(b(a^2)+(axxb)-a(a.b))/(axxb)^2`
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