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A weight of 100N is suspended by two wir...

A weight of 100N is suspended by two wires made by steel and copper as shown in figure length of steel wire is 1m and copper wire is `sqrt(3)m`. Find ratio of change in length of copper wire `(Deltal_(c))` to change in length of steel wire `(Deltal_(s))`. given Young's modulus `Y_("Steel") =2xx10^(11) N//m^(2),Y_("Copper")=1xx10^(11) N//m^(2)`

Text Solution

Verified by Experts


`(T_(s))/2=T_(c)(sqrt(3))/2`
`(T_(s))/2=T_(c)(sqrt(3))/2`
`T_(s)=sqrt(3)T_(c)`
`(Deltal_(C))/(Deltal_(s))=((T_(c))/(T_(S)))((l_(c))/(l_(s)))((Y_(s))/(Y_(c)))=(1/(sqrt(3)))((sqrt(3))/1)((2xx10^(11))/(1xx10^(11)))=2`
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