Home
Class 12
PHYSICS
A sample of monoatomic gas undergoes dif...

A sample of monoatomic gas undergoes different thermodynamic process. Q=Heat given to the gas, W=work done by the gas, U=Change in internal energy of the gas.
The sample of monoatomic gas undergoes a process as represented by P-V graph (if `P_(0)V_(0)=1//3 RT_(0)`)

`(P) W_(1to2)=1//3 RT_(0) " " (Q) Q_(1 to 2 to 3) =11//6 RT_(0)`
`(R) U_(1 to 2) =RT_(0)//2" " (S) W_(1to2to3) =1//3 RT_(0)`
Which of the following option are correct

A

P,Q,R,S are correct

B

Only P,Q are correct

C

Only R,S are correct

D

Only P,R,S correct

Text Solution

Verified by Experts

`W_(1-2)=P_(0)V_(0)=1//3 RT_(0)`
`Q_(2t- 3)=nC_(v)DeltaT=nf/2R DeltaT=f/2 2V_(0) P_(0)=fP_(0)V_(0)=RT_(0)`
`Q_(1-2)=nC_(p)DeltaT=n(f/2+1) R Delta T=5/2. P_(0)V_(0)=5/6 RT_(0)`
`W_(1-2-3)=1//3 RT_(0)`
`U_(1-2)=nC_(V)DeltaT`
`=n3/2 RT_(0)`
`=(RT_(0))/2`
Promotional Banner

Topper's Solved these Questions

  • JEE ADVANCED

    JEE ADVANCED PREVIOUS YEAR|Exercise MULTIPLE CHOICE QUESTIONS|22 Videos
  • JEE ADVANCED

    JEE ADVANCED PREVIOUS YEAR|Exercise SECTION-III (Comprehension Type )|3 Videos
  • JEE (ADVANCE) 2020

    JEE ADVANCED PREVIOUS YEAR|Exercise SECTION 3|6 Videos
  • JEE ADVANCED 2020

    JEE ADVANCED PREVIOUS YEAR|Exercise SECTION-3|6 Videos

Similar Questions

Explore conceptually related problems

A sample of monoatomic gas undergoes a process as represented by T-V graph (if P_(0)V_(0)=1//3 RT_(0) ) then (P) W_(1to2)=1/3 RT_(0)ln2" " (Q)_(1to2to3)=(RT_(0))/6 (2ln(2)+3) (R) U_(1to2)=0" " (S) W_(1to2to3)=(RT_(0))/3 ln2 Which of the following option are correct:

A monoatomic ideal gas undergoes a process ABC . The heat given to the gas is

One mole of a monoatomic ideal gas undergoes a thermodynamic process such that V^3/T^2 = constant. Then,

A monoatomic gas undergoes a process given by 2dU+3dW=0 , then what is the process

V-T graph of a process of monoatomic ideal gas is shown in figure. Change in internal energy of the gas is zero in process(s)-

A certain amount of an ideal monoatomic gas undergoes a thermodynamic process such that VT^(2)= constat where V= volume of gas, T= temperature of gas. Then under process

An ideal diatomic gas undergoes a thermodynamic process as shown in the P-V diagram. The process AB is isochoric while the process BC is isothermal. The total heat gain to the gas in the process is nearly (use ln 2=0.7 )

An ideal monoatomic gas undergoes a process in which its internal energy U and density rho vary as Urho = constant. The ratio of change in internal energy and the work done by the gas is

One mole of a monoatomic ideal gas undergoes the process ArarrB in the given P-V diagram. What is the specific heat for this process?

Two moles of an ideal monoatomic gas undergo a cyclic process which is indicated on a P -U diagram, where U is the internal energy of the gas. The work done by the gas in the cycle is k xx 10^(2) In2 . Find k .