Home
Class 12
PHYSICS
The free length of all four string is va...

The free length of all four string is varied from `L_(0)` to `2L_(0)`. Find the maximum fundamental frequency of 1,2,3,4 in terms of `f_(0)` (Tension is same in all strings)
`{:((A),"String" (mu)-1,(P),1),((B),"String" (2mu)-2,(Q),1//2),((C),"String" (3mu)-3,(R),1/(sqrt(2))),((D),"String" (4mu)-4,(S),1/(sqrt(3))),(,,(T),1//16),(,,(U),3//16):}`

Text Solution

Verified by Experts

The correct Answer is:
`(A) to P,BtoR,(C)toS,(D)toQ`
Fundamental frequency is maximum length is minimum i.e. `L_(0)`
Case-1: `L=L_(0),T=T_(0),f=f_(0), f_(1)=1/(2L_(0))sqrt((T_(o))/(mu))`
Case-2: `f_(2)=1/(L_(0))sqrt((T_(2))/(2mu))=(f_(0))/(sqrt(2))`
Case-3: `f_(3)=1/(L_(0))sqrt((T_(2))/(3mu))=(f_(o))/(sqrt(3))`
Case-4: `f_(4)=1/(L_(0))sqrt((T_(2))/(4mu))=(f_(0))/2`
Promotional Banner

Topper's Solved these Questions

  • JEE ADVANCED

    JEE ADVANCED PREVIOUS YEAR|Exercise MULTIPLE CHOICE QUESTIONS|22 Videos

  • JEE ADVANCED

    JEE ADVANCED PREVIOUS YEAR|Exercise SECTION-III (Comprehension Type )|3 Videos

  • JEE (ADVANCE) 2020

    JEE ADVANCED PREVIOUS YEAR|Exercise SECTION 3|6 Videos

  • JEE ADVANCED 2020

    JEE ADVANCED PREVIOUS YEAR|Exercise SECTION-3|6 Videos

Similar Questions

Explore conceptually related problems

Length of string og musical instrument is varied from L_(o) to 2L_(o) in 4 different cases. Wire is made of different materials of mass per unit length mu,2mu,3mu,4mu respectively. For first case (string -1) length is L_(o) , Tension is T_(o) then fundamental frequency is f_(o), for second case length of the string is (3L_(o))/2 ( 3^(rd) Harmonic), for thid case length of the string is (5L_(o))/4 ( 5^(th) Harmonic) and for the fouth case length of the string is (7L_(o))/4 ( 14^(th) harmonic). if frequency of all is same then tension in string in terms of T_(o) will be: {:((A),"String-1",(P),T_(0)),((B),"String-2",(Q),(T_(0))/(sqrt(2))),((C),"String-3",(R),(T_(o))/2),((D),"String-4",(S),(T_(o))/16),(,,(T),(3T_(o))/16):}

When tension of a string is increased by 2.5 N, the initial frequency is altered in the ratio of 3:2. The initial tension in the string is

If v_(1) , v_(2) and v_(3) are the fundamental frequencies of three segments of stretched string , then the fundamental frequency of the overall string is

Under the action of load F_(1), the length of a string is L_(1) and that under F_(2), is L_(2). The original length of the wire is

On increasing the tension in the string by 10 kg wt, the fundamental frequency increases in the ratio of 1 : 2. Calculate the initial tension in the string.

A string of length l is divided into four segments of fundamental frequencies f_(1), f_(2), f_(3), f_(4) respectively. The original fundamental frequency f of the string is given by

If n_1,n_2 and n_3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by

When a string is divided into three segments of length l_1,l_2 and l_3 the fundamental frequencies of these three segments are f_1,f_2 and f_3 respectively. The original fundamental frequency f of the string is