Consider the reaction

Identify `A, X, Y and Z`

Options

A. A- Methoxymethane, X Ethanol, Y-Ethanoic acid, Z-Semticarbazide
B. A- Ethanal, X-Ethanol , Y-But-2-enal, Z-Semticarbazone
C. A-Ethanol, X-Acetaldehyde, Y-Butanone, Z-hydrazine
D. A-Methoxymrthane , X-Ethnoic acid, Y-Acetate ion, , Z-hydrazine

Answer

B

Explanation

As 'A' gives silver mirror test this means it is aldehyde.
As 'X' is `C_(2)H_(6)O` and with `Cu//573 K` to give aldehyde. This means X is 1 alcohol i.e., `CH_(3)CH_(2)OH`
`CH_(3)-overset((X))underset("Ethanol")(CH_(2))-OHoverset(Cu//300^(@)C)toCH_(3)-underset((A))(CH_(3)=0`