If the difference between the roots of the equation `x^(2)-px+q=0` is the same as the difference of the roots of the equation `x^(2)-qx+p=0` ,show that `p+q+4=0` or p=q.

if the difference of the roots of the equation x^(2)-px +q=0 is unity.

If the roots of the equation x^(2)-px+q=0 differ by unity then

If difference of roots of the equation x^(2)-px+q=0 is 1, then p^(2)+4q^(2) equals-

If the difference between the roots of x^2+ax+b=0 is equal to the difference between the roots of x^2+px+q=0 then a^2-p^2=

If the difference between the real roots of x^(2)+px+q=0 is the same as the difference between the real roots of x^(2)+qx+p=0 and p!=q, then the absolute value of (p+q) is

The roots of the equation x^(2)+px+q=0 are 1 and 2 .The roots of the equation qx^(2)-px+1=0 will be