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If tan theta = (20)/(21), then cos theta...

If `tan theta = (20)/(21),` then `cos theta` is equal to

A

`pm(20)/(41)`

B

`pm(1)/(21)`

C

`pm(21)/(29)`

D

`pm(20)/(21)`

Text Solution

AI Generated Solution

The correct Answer is:
To find \( \cos \theta \) given that \( \tan \theta = \frac{20}{21} \), we can follow these steps: ### Step 1: Understand the relationship of tangent We know that: \[ \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{20}{21} \] This means we can represent the opposite side (perpendicular) as 20 and the adjacent side (base) as 21. ### Step 2: Draw a right triangle We can visualize this as a right triangle where: - The opposite side (AC) = 20 - The adjacent side (AB) = 21 - The hypotenuse (BC) is unknown. ### Step 3: Use the Pythagorean theorem According to the Pythagorean theorem: \[ BC^2 = AC^2 + AB^2 \] Substituting the values we have: \[ BC^2 = 20^2 + 21^2 \] Calculating the squares: \[ BC^2 = 400 + 441 = 841 \] Thus, we find: \[ BC = \sqrt{841} = 29 \] ### Step 4: Calculate \( \cos \theta \) Now that we have all sides of the triangle, we can find \( \cos \theta \): \[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{AB}{BC} = \frac{21}{29} \] ### Step 5: Consider the sign of \( \cos \theta \) Since \( \theta \) is in the first quadrant (where both sine and cosine are positive), we conclude: \[ \cos \theta = \frac{21}{29} \] ### Final Answer Thus, the value of \( \cos \theta \) is: \[ \cos \theta = \frac{21}{29} \] ---
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