Home
Class 11
MATHS
(sin 3A -cos ((pi)/(2)-A))/(cos A+ cos (...

`(sin 3A -cos ((pi)/(2)-A))/(cos A+ cos (pi+3A))=`

A

`tan A`

B

`cot A`

C

`tan 2A`

D

`cot 2A`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • FACTORIZATION FORMULAE

    TARGET PUBLICATION|Exercise CRITICAL THINKING|34 Videos

  • FACTORIZATION FORMULAE

    TARGET PUBLICATION|Exercise COMETITIVE THINKING|34 Videos

  • CIRCLE AND CONICS

    TARGET PUBLICATION|Exercise EVALUATION TEST|28 Videos

  • PROBABILITY

    TARGET PUBLICATION|Exercise EVALUATION TEST|8 Videos

Similar Questions

Explore conceptually related problems

Delta ABC, (sin ((2 pi) / (3) -A) + sin ((2 pi) / (3) -B) + sin ((2 pi) / (3) -C)) / (cos ( (pi) / (3) - (A) / (2)) * cos ((pi) / (3) - (B) / (2)) * cos ((pi) / (3) - (C) / (2))))

(cos ^ (2) ((pi) / (4) -A) -sin ^ (2) ((pi) / (4) -A)) / (cos ^ (2) ((pi) / (4) + A) + sin ^ (2) ((pi) / (4) + A) =)

Prove that (i) "cos " ((pi)/(3) +x) =(1)/(2) ( " cos " x - sqrt(3) sin x) (ii) " sin " ((pi)/(4) + x) + " sin " ((pi)/(4)-x) =sqrt(2) " cos " x (iii) (1)/(sqrt(2)) " cos ((pi)/(4) + x) = (1)/(2) " (cos x - sin x) " (iv) " cos x + cos " ((2pi)/(3) +x) + " cos " ((2pi)/(3)-x) =0

[sin ((pi) / (2) -x) + sin (pi-x)] ^ (2) + [(cos ((3 pi) / (2) -x) + cos (2 pi-x)] ^ (2) =

cos A+cos((4 pi)/(3)-A)+cos((4 pi)/(3)+A)=0

4sin ((pi) / (6)) sin ^ (2) ((pi) / (3)) + 3cos ((pi) / (3)) tan ((pi) / (4)) + cos e ^ ( 2) ((pi) / (2)) = 2sec ^ (2) ((pi) / (4))

cos ^ (2) (0) + cos ^ (2) ((pi) / (6)) + cos ^ (2) ((pi) / (3)) + cos ^ (2) ((pi) / ( 2))

The sum cos ((pi) / (9)) + cos ((2 pi) / (9)) + cos ((3 pi) / (9)) + ... + cos ((17 pi) / (9 )) =

Prove that (i) "sin " (7pi)/(12) " cos " (pi)/(2) - "cos " *(7pi)/(12) " sin " (pi)/(4) = (sqrt(3))/(2) (ii) " sin " (pi)/(4) " cos " (pi)/(2) + "cos"(pi)/(4) " sin " (pi)/(12) = (sqrt(3))/(2) (iii) " cos " (2pi)/(3) " cos " (pi)/(4) - " sin " (2pi)/(3) " sin " (pi)/(4) =(-(sqrt(3) +1))/(2sqrt(2))

(a ^ (3) (sin ^ (3) pi) / (2) -b ^ (3) cos ^ (3) (pi)) / (a ^ (2) (sin ^ (2) pi) / ( 2) + ab cos pi-b ^ (2) cos pi)