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The equation of a circle with origin as ...

The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3 a is

A

`x ^(2) + y^(2)=9a ^(2)`

B

`x ^(2) + y^(2) =16 a ^(2)`

C

`x ^(2) + y^(2) =4a ^(2)`

D

`x ^(2) + y^(2) =a ^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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The equation of the circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is: a x^(2)+y^(2)=9a^(2) b) x^(2)+y^(2)=16a^(2) c) x^(2)+y^(2)=4a^(2) d) x^(2)+y^(2)=a^(2)

The equation of circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is x^(2)+y^(2)=a^(2)x^(2)+y^(2)=4a^(2)x^(2)+y^(2)=16a^(2)x^(2)+y^(2)=9a^(2)

Knowledge Check

  • The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is

    A
    `x^(2)+y^(2) =9a^(2)`
    B
    `x^(2)+y^(2)=16a^(2)`
    C
    `x^(2)+y^(2) =4a^(2)`
    D
    `x^(2)+y^(2) =a^(2)`

  • The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a, is

    A
    `x^(2)+y^(2)=9a^(2)`
    B
    `x^(2)+y^(2)=16a^(2)`
    C
    `x^(2)+y^(2)=4a^(2)`
    D
    `x^(2)+y^(2)=a^(2)`

  • The equation of a circle with centre at origin and passing through the vertices of an equilateral triangle whose median is of length 3a is

    A
    `x^(2)+y^(2)=a^(2)`
    B
    `x^(2)+y^(2)=4a^(2)`
    C
    `x^(2)+y^(2)=9a^(2)`
    D
    none

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