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If cosA=mcosB, then...

If `cosA=mcosB`, then

A

`cot ((A+B)/(2)) =(m+1)/(m-1) tan ((B-A)/(2))`

B

`tan ((A+B)/(2)) =(m+1)/(m-1) cot ((B-1)/(2))`

C

`cot ((A+B)/(2)) =(m+1)/(m-1) cot ((B-A)/(2))`

D

None of these

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The correct Answer is:
A
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