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If A=[(i,0),(0,(i)/(2))] where(i=sqrt(-1...

If `A=[(i,0),(0,(i)/(2))]` where`(i=sqrt(-1))`, then `A^(-1)=`

A

`[(i,0),(0,(i)/(2))]`

B

`[(-i,0),(0,-2i)]`

C

`[(i,0),(0,2i)]`

D

`[(0,i),(2i,0)]`

Text Solution

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The correct Answer is:
B
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    `{:[(1-i,i),(-i,1-i)]:}`
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