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[(1,3,-2),(-3,0,-5),(2,5,0)] =A [(1,0,0)...

`[(1,3,-2),(-3,0,-5),(2,5,0)] =A [(1,0,0),(0,1,0),(0,0,1)]` then, `C_(2) rarr C_(2)-3C_(1) and C_(3) rarr C_(3) +2C_(1)` gives

A

`[(1,0,0),(3,-9,11),(-2,1,4)] =A [(-1,3,2),(0,-1,0),(0,0,-1)]`

B

`[(1,0,0),(-3,-1,-4),(2,-9,11)] =A [(1,-3,2),(0,1,0),(0,0,1)]`

C

`[(1,0,0),(-3,1,4),(-2,9,-11)] =A [(-1,3,2),(0,-1,0),(0,0,-1)]`

D

`[(1,0,0),(-3,9,-11),(2,-1,4)] =A [(1,-3,2),(0,1,0),(0,0,1)]`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Given A = [(1,2,-3),(5,0,2),(1,-1,1)] and B - [(3,-1,2),(4,2,5),(2,0,3)] . The matrix C such that A + 2C = B is

    A
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    B
    `[((5)/(2),(3)/(2),1),(-(1)/(2),(7)/(2),(9)/(2)),((11)/(2),(9)/(2),8)]`
    C
    `[(1,2,4),((3)/(2),(11)/(2),(13)/(14)),(4,(9)/(2),(7)/(2))]`
    D
    None of these

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