An electron of mass m has de broglie wav...

An electron of mass m has de broglie wavelength `lamda` when accelerated through a potential difference V . When a proton of mass M is accelerated through a potential difference 9V, the de broglie wavelength associated with it will be (Assume that wavelength is determined at low voltage ) .

`lambda/5 sqrt(M/n)`

`lambda/3 (M)/m`

`lambda/3 sqrt(m/M)`

`lambda/3 m/M`

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