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Let 'A' be the area swept by the line jo...

Let `'A'` be the area swept by the line joining the earth and the sun during Feb `2012`. The area swept by the same line during the first week of that month is

A

`A//4`

B

`7A//29`

C

`A`

D

`7A//30`

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The correct Answer is:
To solve the problem, we need to determine the area swept by the line joining the Earth and the Sun during the first week of February 2012, given that the area swept during the entire month of February 2012 is \( A \). ### Step-by-Step Solution: 1. **Identify the total days in February 2012**: February 2012 is a leap year, so it has 29 days. \[ \text{Total days in February 2012} = 29 \text{ days} \] 2. **Determine the area swept in one day**: The area swept in 29 days is given as \( A \). To find the area swept in one day, we divide \( A \) by the total number of days. \[ \text{Area swept in one day} = \frac{A}{29} \] 3. **Calculate the area swept in the first week (7 days)**: Since the area swept in one day is \( \frac{A}{29} \), the area swept in 7 days (the first week) can be calculated by multiplying the area swept in one day by 7. \[ \text{Area swept in 7 days} = 7 \times \frac{A}{29} = \frac{7A}{29} \] 4. **Conclusion**: The area swept by the line joining the Earth and the Sun during the first week of February 2012 is \( \frac{7A}{29} \). ### Final Answer: The area swept during the first week of February 2012 is \( \frac{7A}{29} \). ---

To solve the problem, we need to determine the area swept by the line joining the Earth and the Sun during the first week of February 2012, given that the area swept during the entire month of February 2012 is \( A \). ### Step-by-Step Solution: 1. **Identify the total days in February 2012**: February 2012 is a leap year, so it has 29 days. \[ \text{Total days in February 2012} = 29 \text{ days} ...
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