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Particles of masses `m_1` and `m_2` are at a fixed distance apart. If the gravitational field strength at `m_1` and `m_2` are `vec I_1` and `vec I_2` respectively. Then,

A

`m_(1)vec(I)_(1)+m_(2)vec(I)_(2)=0`

B

`m_(1)vec(I)_(2)+m_(2)vec(I)_(1)=0`

C

`m_(1)vec(I)_(1)-m_(2)vec(I)_(2)=0`

D

`m_(1)vec(I)_(2)-m_(2)vec(I)_(1)=0`

Text Solution

Verified by Experts

The correct Answer is:
A

`vec(I)_(1)=(Gm_(2))/(d^(2))` and `vec(I)_(2)=-(Gm_(1))/(d^(2))`
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