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An object of mass m is at rest on earth'...

An object of mass `m` is at rest on earth's surface. Escape speed of this object is `V_(e)`. Same object is orbiting the earth with `h=R`, then escape speed is `V_(e)^(1)`. Then

A

`V_(e)^(1)=(V_(e))/(4)`

B

`V_(e)=2V_(e)^(1)`

C

`V_(e)=sqrt2V_(e)^(1)`

D

`V_(e)^(1)=sqrt2V_(e)`

Text Solution

Verified by Experts

The correct Answer is:
D
`1/2mv_(0)^(2)-(Gmn)/((R+h))=0`
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