A thin rod of length L is bent to form a...

A thin rod of length `L` is bent to form a semi circle. The mass of the rod is `M`. What will be the gravitational potential at the centre of the circle?

`(-GM)/L`

`(-GM)/(2piL)`

`(-piGM)/(2L)`

`(-piGM)/L`

Text Solution

Verified by Experts

The correct Answer is:

`L=pir ` but `V=(-GM)/r`

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