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A particle hanging from a massless sprin...

A particle hanging from a massless spring stretches it by `2 cm` at the earth's surface. How much will the same particle stretch the spring at a height? Of `2624Km` from the surface of the earth? (Radius of the earth`=6400 km`)

A

`1 cm`

B

`2 cm`

C

`3 cm`

D

`4cm`

Text Solution

Verified by Experts

The correct Answer is:
A
`mg=Kx, x propg` here, `(g_(h))/g=(R^(2))/((R+h)^(2))`
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