The difference in PE of an object of mas...

The difference in `PE` of an object of mass `10 kg` when it is taken from a height of `6400 Km` to `12800 Km` from the surface of the earth is `(M_(E)=6xx10^(24)kg)`

`1.045xx10^(8) J`

`1.565xx10^(8)J`

`2.65xx10^(8) J`

`4.5xx10^(8)J`

Text Solution

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The correct Answer is:

`P.E.=-GMm(1/(R_(1))-1/(R_(2)))`

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