The K.E. of a satellite is 10^(4)J. It's...

The `K.E.` of a satellite is `10^(4)J`. It's `P.E.`is

`-10^(4) J`

`2xx10^(4)J`

`-2xx10^(4)J`

`-4xx10^(4)J`

Text Solution

Verified by Experts

The correct Answer is:

`P.E.=-2(K.E.)`

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NARAYNA-GRAVITATION-LEVEL -I(H.W)

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