Home
Class 11
PHYSICS
The energy required to move a body of ma...

The energy required to move a body of mass`m` from an orbit of radius `3R` to `4R` is

A

`(GMm)/(2R)`

B

`(GMm)/(6R)`

C

`(GMm)/(12R)`

D

`(GMm)/(24R)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the energy required to move a body of mass `m` from an orbit of radius `3R` to `4R`, we will follow these steps: ### Step 1: Understand the Total Energy in Orbit The total energy \( E \) of a body in a circular orbit of radius \( R \) is given by the formula: \[ E = -\frac{GMm}{2R} \] where \( G \) is the gravitational constant, \( M \) is the mass of the central body, and \( m \) is the mass of the orbiting body. ### Step 2: Calculate Total Energy at Radius \( 3R \) Using the formula for total energy, we calculate the energy at the radius \( 3R \): \[ E_{3R} = -\frac{GMm}{2 \cdot 3R} = -\frac{GMm}{6R} \] ### Step 3: Calculate Total Energy at Radius \( 4R \) Next, we calculate the energy at the radius \( 4R \): \[ E_{4R} = -\frac{GMm}{2 \cdot 4R} = -\frac{GMm}{8R} \] ### Step 4: Find the Change in Energy The energy required to move the body from the orbit of radius \( 3R \) to \( 4R \) is the difference in total energy: \[ \Delta E = E_{4R} - E_{3R} \] Substituting the values we calculated: \[ \Delta E = \left(-\frac{GMm}{8R}\right) - \left(-\frac{GMm}{6R}\right) \] This simplifies to: \[ \Delta E = -\frac{GMm}{8R} + \frac{GMm}{6R} \] ### Step 5: Simplify the Expression To combine the fractions, we need a common denominator, which is \( 24R \): \[ \Delta E = \left(-\frac{3GMm}{24R} + \frac{4GMm}{24R}\right) \] This results in: \[ \Delta E = \frac{1GMm}{24R} \] ### Final Answer Thus, the energy required to move the body from an orbit of radius \( 3R \) to \( 4R \) is: \[ \Delta E = \frac{GMm}{24R} \]

To solve the problem of finding the energy required to move a body of mass `m` from an orbit of radius `3R` to `4R`, we will follow these steps: ### Step 1: Understand the Total Energy in Orbit The total energy \( E \) of a body in a circular orbit of radius \( R \) is given by the formula: \[ E = -\frac{GMm}{2R} \] where \( G \) is the gravitational constant, \( M \) is the mass of the central body, and \( m \) is the mass of the orbiting body. ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    NARAYNA|Exercise LEVEL-II (H.W)|32 Videos
  • GRAVITATION

    NARAYNA|Exercise LEVEL-V|54 Videos
  • GRAVITATION

    NARAYNA|Exercise NCERT BASED QUESTIONS|26 Videos
  • FRICTION

    NARAYNA|Exercise Passage type of questions I|6 Videos
  • KINETIC THEORY OF GASES

    NARAYNA|Exercise LEVEL-III(C.W)|52 Videos

Similar Questions

Explore conceptually related problems

Energy required to move a body of mass m from an orbit of radius 2R to 3R is

The energy requierd to remove an earth satellite of mass m from its orbit of radius r to infinity is

The energy required to move an earth satellites of mass m from a circular orbit of radius 2 R to a radius 3 R is " " (R is radius of the earth)

The kinetic energy needed to project a body of mass m from the earth surface (radius R) to infinity is

In order to shift a body of mass m from a circular orbit of radius 3R to a higher orbit of radius 5R around the earth, the work done is

A satellite of mass 'm' is revolving in an orbit of radius 2 R. The minimum energy required to lift it into another orbit of radius 3R is (R is radius of the earth and g is acceleration due to gravity on its surface. )

Energy required in moving a body of mass m from a distance 2R to 3R from centre of earth of mass M is

NARAYNA-GRAVITATION-LEVEL -I(H.W)
  1. The escape velocity of a sphere of mass m is given by

    Text Solution

    |

  2. A body is projected up with a velocity equal to 3//4th of the escape v...

    Text Solution

    |

  3. A spacecraft is launched in a circular orbit very close to earth. What...

    Text Solution

    |

  4. If the escape velocity on the earth is 11.2 km//s, its value for a pla...

    Text Solution

    |

  5. The escape velocity of a body from earth's surface is ve. The escape v...

    Text Solution

    |

  6. The escape velocity of a body from the surface of the earth is V(1) an...

    Text Solution

    |

  7. The ratio of the orbital speeds of two satellites of the earth if the ...

    Text Solution

    |

  8. An artificial satellite is revolving in a circular orbit at height of ...

    Text Solution

    |

  9. The mean radius of the orbit of a satellite is 4 times as great as tha...

    Text Solution

    |

  10. If the mass of earth were 4 times the present mass, the mass of the mo...

    Text Solution

    |

  11. A satellite of mass m revolves around the earth of mass M in a circula...

    Text Solution

    |

  12. A satellite of mass m is in a circular orbit of radius r round the Ear...

    Text Solution

    |

  13. Two satellite of masses 400 kg,500kg are revolving around earth in dif...

    Text Solution

    |

  14. Angular momentum of a satellite revolving round the earth in a circula...

    Text Solution

    |

  15. The K.E. of a satellite is 10^(4)J. It's P.E.is

    Text Solution

    |

  16. The energy required to move a body of massm from an orbit of radius 3R...

    Text Solution

    |

  17. K.E. of an orbiting satellite is K. The minimum additional K.E. requir...

    Text Solution

    |

  18. Imagine a geo-stationary satellite of the earth which is used as an in...

    Text Solution

    |

  19. The height of a geo-stationary satellite above the centre of the earth...

    Text Solution

    |

  20. How much faster than it's normal rate should the earth rotate about it...

    Text Solution

    |