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The angular velocity of the earth's rota...

The angular velocity of the earth's rotation about its axis is `omega`. An object weighed by a spring balance gives the same reading at the equator as at height `h` above the poles. The value of `h` will be

A

`(omega^(2)R^(2))/g`

B

`(omega^(2)R^(2))/(2g)`

C

`(2omega^(2)R^(2))/g`

D

`(2omega^(2)R^(2))/(3g)`

Text Solution

Verified by Experts

The correct Answer is:
B
`F=mg',g'=g-Romega^(2)cos^(2)phi`
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