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A particle is projected from the surface...

A particle is projected from the surface of earth with intial speed of 4 km/s. Find the maximum height attained by the particle. Radius of earth = 6400 km and `g = 9.8 m//s^(2)`

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The correct Answer is:
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`(mghR_(e))/(R_(e)+h)+1/2mv^(2), h=(v^(2))/(2g-(v^(2))/R)=1`
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