If the law of gravitation be such that the force of attraction between two particles vary inversely as the `5//2^(th)` power of their separation then the graph of orbital velocity `v_(0)` plotted against the distance `r` of a satellite from the earth's centre on a log-log scale is shown alongside the slope on a line will be

Options

A. `-3/4`
B. `-3/2`
C. `-1`
D. `-5/2`

Answer

A

Explanation

For `m` closer to `M`
`(GMm)/(9l^(2))-(Gm^(2))/(l^(2))=ma......(1)`
and of the other `m`
`(Gm^(2))/(l^(2))+(GMm)/(16l^(2))=ma.....(2)`
solving (1) and (2), we get `K=7`