In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of `2xx10^(10)Hz` and amplitude `48V//m`. The wavelength of the wave will be-

Options

A. `1.15m`
B. `66.6m`
C. `1.5 cm`
D. `66.6 cm`

Explanation

To find the wavelength of the electromagnetic wave, we can use the formula that relates the speed of light (c), frequency (ν), and wavelength (λ):

\[ \lambda = \frac{c}{\nu} \]

### Step-by-step Solution:

1. **Identify the given values**:
- Frequency (ν) = \(2 \times 10^{10} \, \text{Hz}\)
- Speed of light (c) = \(3 \times 10^8 \, \text{m/s}\)

2. **Substitute the values into the wavelength formula**:
\[ \lambda = \frac{c}{\nu} = \frac{3 \times 10^8 \, \text{m/s}}{2 \times 10^{10} \, \text{Hz}} \]

3. **Perform the division**:
- First, simplify the expression:
\[ \lambda = \frac{3}{2} \times \frac{10^8}{10^{10}} \, \text{m} \]
- This simplifies to:
\[ \lambda = \frac{3}{2} \times 10^{-2} \, \text{m} \]

4. **Calculate the numerical value**:
\[ \lambda = 1.5 \times 10^{-2} \, \text{m} \]

5. **Convert to centimeters**:
- Since \(1 \, \text{m} = 100 \, \text{cm}\):
\[ \lambda = 1.5 \times 10^{-2} \, \text{m} = 1.5 \, \text{cm} \]

### Final Answer:
The wavelength of the wave is \(1.5 \, \text{cm}\).