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An AC rms voltage of 2V having a frequen...

An `AC rms` voltage of `2V` having a frequency of `50KHz` is applied to a condenser of capacity of `10muF`. The maximum value of the magnetic field between the plates of the condenser if the radius of plate is `10cm` is

A

`0.4 p mu`

B

`4pi mu T`

C

`2 mu T`

D

`40pi mu T`

Text Solution

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The correct Answer is:
To find the maximum value of the magnetic field between the plates of a capacitor when an AC rms voltage is applied, we can follow these steps: ### Step 1: Convert Given Values - Given: - AC rms voltage, \( V_{rms} = 2 \, V \) - Frequency, \( f = 50 \, kHz = 50 \times 10^3 \, Hz \) - Capacitance, \( C = 10 \, \mu F = 10 \times 10^{-6} \, F \) - Radius of the plates, \( r = 10 \, cm = 0.1 \, m \) ### Step 2: Calculate Maximum Voltage The maximum voltage \( V_{max} \) can be calculated from the rms voltage using the formula: \[ V_{max} = V_{rms} \times \sqrt{2} \] Substituting the values: \[ V_{max} = 2 \times \sqrt{2} \approx 2.828 \, V \] ### Step 3: Calculate Current The current \( I \) through the capacitor can be calculated using the formula: \[ I = C \frac{dV}{dt} \] For an AC voltage, \( dV/dt \) can be expressed as: \[ \frac{dV}{dt} = 2 \pi f V_{max} \] Substituting the values: \[ \frac{dV}{dt} = 2 \pi (50 \times 10^3) (2.828) \approx 628318.53 \, V/s \] Now, substituting back to find \( I \): \[ I = C \cdot \frac{dV}{dt} = (10 \times 10^{-6}) \cdot (628318.53) \approx 6.283 \, A \] ### Step 4: Calculate Magnetic Field The magnetic field \( B \) between the plates of the capacitor can be calculated using the formula: \[ B = \frac{\mu_0 I}{2 \pi r} \] Where \( \mu_0 = 4 \pi \times 10^{-7} \, T \cdot m/A \). Substituting the values: \[ B = \frac{(4 \pi \times 10^{-7}) (6.283)}{2 \pi (0.1)} \] This simplifies to: \[ B = \frac{(4 \times 10^{-7}) (6.283)}{0.2} = \frac{2.513 \times 10^{-6}}{0.2} \approx 1.2565 \times 10^{-5} \, T \] ### Step 5: Convert to Microtesla To convert the magnetic field from Tesla to microtesla: \[ B \approx 12.565 \, \mu T \] ### Final Answer The maximum value of the magnetic field between the plates of the capacitor is approximately \( 12.57 \, \mu T \). ---

To find the maximum value of the magnetic field between the plates of a capacitor when an AC rms voltage is applied, we can follow these steps: ### Step 1: Convert Given Values - Given: - AC rms voltage, \( V_{rms} = 2 \, V \) - Frequency, \( f = 50 \, kHz = 50 \times 10^3 \, Hz \) - Capacitance, \( C = 10 \, \mu F = 10 \times 10^{-6} \, F \) - Radius of the plates, \( r = 10 \, cm = 0.1 \, m \) ...
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