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A point source of electromagnetic radiat...

A point source of electromagnetic radiation has an average power output of `800W`. The maximum value of electric field at a distance `3.5m` from the source will be `62.6 V/m`, the energy density at a distance `3.5 m` from the source will be- (in `"joule"//m^(3)`)

A

`1.73xx10^(-5)`

B

`1.73xx10^(-6)`

C

`1.73xx10^(-7)`

D

`1.73xx10^(-8)`

Text Solution

Verified by Experts

The correct Answer is:
D
Energy density `U=(1)/(2)epsilon_(0)E_(m)^(2)`
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