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An electruc field of 300V//m is confined...

An electruc field of `300V//m` is confined to a circular area `10 cm` in diameter. If the field is increasing at the rate of `20V//m-s`, the magnitude of magnetic field at a point `15cm` from the centre of the circle will be-

A

`1.85xx10^(-15)T`

B

`1.85xx10^(-16)T`

C

`1.85xx10^(-17)T`

D

`1.85xx10^(-18)T`

Text Solution

Verified by Experts

The correct Answer is:
D
`B=(mu_(0)epsilon_(0))/(2piR)((pid^(2))/(4))(dE)/(dt)`
`=(2xx10^(-7)xx8.85xx10^(-12)xx3.14xx0.01x20)/(4xx0.15)`
`=1.85xx10^(-18)T`
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