Home
Class 12
PHYSICS
A flood light is covered with a fitter t...

A flood light is covered with a fitter than transmits red light. The electric field of the emerging beam is represented a sinusolidal plane wave
`E_(x)=36 sin (1.20xx10^(7)z-3.6xx10^(15)t) V//m`
The average intensity of beam is `"watt"//("metre")^(2)` will be

A

`0.86 W//m^(2)`

B

`1.72 W//m^(2)`

C

`3.44 W//m^(2)`

D

`6.88 W//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`I_(av)=(cepsilon_(0)E_(0)^(2))/(2)=(3xx10^(8)xx8.85xx10^(-12)xx36^(2))/(2)=1.72W/m^(2)`
Promotional Banner

Topper's Solved these Questions

  • ELECTRO MAGNETIC WAVES

    NARAYNA|Exercise NCERT based|8 Videos
  • ELECTRO MAGNETIC WAVES

    NARAYNA|Exercise LEVEL- V|4 Videos
  • ELECTRO MAGNETIC WAVES

    NARAYNA|Exercise LEVEL- II (C.W.)|15 Videos
  • ELECTRO MAGNETIC INDUCTION

    NARAYNA|Exercise Level-II (H.W)|23 Videos
  • ELECTROMAGNETIC INDUCTION

    NARAYNA|Exercise ASSERTION & REASON|6 Videos

Similar Questions

Explore conceptually related problems

A flood light will be covered with filter that transmits red light. The electric field of the emerging beam is represented by a sinusoidal plane wave E_x=38.8sin(1.2xx10^7z-3.6xx10^(15)t)V//m . The average intensity of beam in "watt"//m^2 will be:

The magnetic field of a beam emerging from a filter facing a floodlight is given by B=12xx10^-8sin(1.20xx10^7z-3.60xx10^14t)T . What is the average intensity of the beam?

The magnetic field of a bram emerging from a filter facing a floodlight is given by B= 12 xx 10^(-8 ) sin ( 1.20 xx 10^(7) z- 3.60 xx 10 ^(15) t ) t. what is the average intensity of the beam ?

If the magnetic field in a plane electro-magnetic wave is given by vecB=3xx10^(-8) sin (1.6 xx 10^(3) x + 48 xx 10^(10)t)hatjT, then average intensity of the beam is:

The magnetic component of a polarised wave of light is [B_(x)=(4.0xx10^(-6)T)sin(1.57xx10^(7)m^(-1))y+omegat] . The intensity of light is

The magnetic field in a plane e.m. wave is given by B_y=2xx10^-7sin(0.5xx10^3x+1.5xx10^(11)t) . This e.m. wave is

Electric field associated with a light wave is given E= E_(0) sin [1.57 xx10^(15)t +6.28 xx10^(15) t] V/m. If this light incident on a surface of work function 2.0 eV the stopping potential will be -