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The radiation force experienced by body ...

The radiation force experienced by body exposed to radiation of intensity `I`, assuming surface of body to be perfectly absorbing is:

A

`(piR^(2)I)/(c )`

B

`(piRHI)/(c )`

C

`(IRH)/(2c )`

D

`(IRH)/(c )`

Text Solution

Verified by Experts

The correct Answer is:
D
`F=(I)/(c )xx`effective area
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Knowledge Check

  • The radiation emitted by a perfectly black body is proportional to

    A
    absolute temperature
    B
    fourth root of absolute temperature
    C
    fourth power of absolute temperature
    D
    square of absolute temperature

  • Consider a sphere of radius R exposed to radition of instensity I as shown in figure . If surface of sphere is partially reflection and reflection coefficient is 0.3, then radiation force experienced is :

    A
    `(pi R^(2)I)/(c)`
    B
    `(1.7pi R^(2)I)/(c)`
    C
    `(0.3pi R^(2)I)/(c)`
    D
    None of these

  • A ferfectly black body is one which absorbs radiation of

    A
    all wavelengths
    B
    large wavelengths
    C
    small wavelengths
    D
    infrared wavelengths

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