Home
Class 12
PHYSICS
The maximum peak-to-peak voltage of an A...

The maximum peak-to-peak voltage of an `AM` wave is `16 mV` and the minimum peak-to-peak voltage is `4 mV`. The modulation factor is equal to

A

`0.6`

B

`0.3`

C

`0.8`

D

`0.25`

Text Solution

Verified by Experts

The correct Answer is:
A

`mu=((16-4)//2)/((16+4)//2)`
Promotional Banner

Topper's Solved these Questions

  • COMMUNICATION SYSTEM

    NARAYNA|Exercise NCERT Based|16 Videos
  • COMMUNICATION SYSTEM

    NARAYNA|Exercise Level-I(H.W)|11 Videos
  • COMMUNICATION SYSTEM

    NARAYNA|Exercise Level-II(C.W)|34 Videos
  • CAPACITANCE

    NARAYNA|Exercise Previous IIT-JEE|16 Videos
  • CURRENT ELECTRICITY

    NARAYNA|Exercise Level 6|43 Videos

Similar Questions

Explore conceptually related problems

The maximum peak to peak voltage of an AM wire is 24 mV and the minimum peak to peak voltage is 8 m V. The modulation factor is

The maximum peak ro peak voltage of an AM wire is 24 mV and the minimum peak to peak voltage is 8mV . The modulation factor is

The maximum peak to peak voltage of an AM wave is 16 m V and the minimum peak to peak voltage is 8 m V. What is the modulation index ?

If minimum voltage in an AM wave was found to be 2V and maximum voltage 10V . The % modulation index

If minimum voltage in an AM wave was found to be 1.1 V and maximum voltage 10V . The % modulation index

The peak voltage in a 220 V AC source is

If the maximum and minimum voltages of an AM wave are V_(max.)andV_(min.) respectively then modulation factor -

if the maximum and minimum voltage of AM wave are V_(max) and V_(min) , respectively then modulation factor

The peak voltage of an ac supply is 440 V, then its rms voltage is