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A 400 watt carrier is modulated to a dep...

A `400 watt` carrier is modulated to a depth of `80%`. Calculate the total power in the modulated wave.

A

`528 W`

B

`128 W`

C

`256 W`

D

`400 W`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(Total)=P_(C)(1+(m^(2))/(2))=528 watts`
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