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A sky wave with a frequency 64.4 MHz is ...

A sky wave with a frequency `64.4 MHz` is incident on `D`-region of earth's atmosphere at `45^(@)`. The angle of refraction is (electron density for `D`-region is `400 "electron"//cm^(3)`)

A

`60^(@)`

B

`90^(@)`

C

`45^(@)`

D

`15^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
`n_(eff)=n_(0)sqrt(1-(80.5N)/(v^(2)))`
`=1sqrt(1-(80.5xx400xx10^(6))/((64.4xx10^(6))^(2)))`, `~~1`
Also `n_(eff)=(sini)/(sinr)impliessini=sinr`, `impliesi=r=45^(@)`
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