While finding specific heat capacity usi...

While finding specific heat capacity using calorimeter, error might occur due to:

Absence of water equivalent

Absence of heat loss reducing covers.

Presence of stirrer

Absence of stirrer

Text Solution

Verified by Experts

The correct Answer is:

A, B

Water equivalent is important since the calorimeter also will lose or gain heat. Heat loss has to reduced (by Radiation and//or Convection).
So, choices (`a`) and (`b`) are correct.
Use of stirrer, maintains uniform temperture So, choices (`c`) and (`d`) are wrong.

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The specific heat capacity is

constant for each material

depends on the conditions under which it is measured

same for a material at all conditions

the statement 'a', 'b' and 'c' are correct

Specific heat capacity is given by

`(dQ//d theta)`

`(1//m)dQ//d theta`

`(1//m)d theta//d Q`

`m(dQ//d theta)`

The specific heat capacity of water is

`4.2 J kg^(-1)""^(@)C^(-1)`

`4.2 J g^(-1)""^(@)C^(-1)`

` 1 J g^(-1)""^(@)C^(-1)`

`1 J kg^(-1)""^(@)C^(-1)`