Home
Class 12
PHYSICS
In Searle's experiment, the diameter of ...

In Searle's experiment, the diameter of the wire as measured by a screw gauge of least count `0.01cm` is `0.050cm`. The length, measured by a scale of least count `0.1cm`, is `110.0cm`. When a weight of `50N` is suspended from the wire, the extension is measure to be `0.125 cm` by a micrometer of least count `0.01cm`. Find the maximum error in the measurement of Young's modulus of the material of the wire from these data..

Text Solution

Verified by Experts

The correct Answer is:
4.89
Maximum percentage error in `Y` is given by
`y=(W)/((piD^(2))/(4))xx(L)/(x)`
`((DeltaY)/(Y))_(max)=2((DeltaD)/(D))+(Deltax)/(x)+(DeltaL)/(L)`
`=2((0.001)/(0.05))+((0.001)/(0.125))+((0.1)/(110))=0.0489`
So maximum percentage error`= 4.89%`
Promotional Banner

Topper's Solved these Questions

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Level-VI(Single answer)|25 Videos

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Comprehension type|6 Videos

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Asserson and Reason|4 Videos

  • ELECTROSTATICS AND GAUSS LAW

    NARAYNA|Exercise Intergers type question|11 Videos

  • MAGNETISM

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos

Similar Questions

Explore conceptually related problems

In searle's experiment, the diameter of the wire, as measured by a screw gauge of least count 0.001 cm is 0.500 cm. The length, measured by a scale of least count 0.1cm is 110.0cm. When a weight of 40N is suspended from the wire, its extension is measured to be 0.125 cm by a micrometer of least count 0.001 cm. Find the Young's modulus of the meterial of the wire from this data.

In Searle's apparatus diameter of the wire was measured 0.05 cm by screw gauge of least count 0.001 cm. The length of wire was measured 110 cm by meter scale of least count 0.1 cm. An external load of 50 N was applied. The extension in length of wire was measured 0.125 cm by micrometer of least count 0.001 cm. Find the maximum possible error in measurement of Young's modulus.

In Searl's experiment, which is used to find Young's Modulus of elasticity, the diameter of experimental wire is D = 0.05cm (measured by a scale of least count 0.001cm ) and length is L = 110cm (measured by a scale of least count 0.1cm ). A weight of 50N causes an extension of X = 0.125 cm (measured by a micrometer of least count 0.001cm ). find the maximum possible error in the values of Young's modulus. Screw gauge and meter scale are free error.

The diameter of a wire as measured by a screw gauge was found to be 1.002cm, 1.000cm and 1.006cm . The absoulue error in the first reading.

If the zero error correction of a screw gauge with least of count 0.01 mm is +0.05 mm

The diameter of a wire as measured by a screw gauge was found to be 1.002cm, 1.004cm and 1.006cm . The absoulue error in the third reading is

A student measured the diameter of a wire using a screw gauge with least count 0.001 cm and listed the measurements. The correct measurement is

A student measured the diameter of a wire using a screw gauge with least count 0.001cm and listed the measurement. The correct measurement is