If we use very thin and long wire, then

Options

A. Sensitivity `(("output")/("input")=(DeltaX)/(DeltaW))` of experiment increases
B. Young's modulus will remain unchanged
C. Wire may break or yield during loading.
D. All of the above

Answer

D

Explanation

Maximum permissible error in `Y` due to error in measuring `l_(2)`, `r`, `x` (If these is no tolerance in mass):
`Y=(l_(0))/(pir^(2)x)mg`
If there is no tolarence in mass max permissible error in `Y` is
`((Deltay)/(y))_(max)=(Deltal_(0))/(l_(0))+2(Deltar)/(r)+(Deltax)/(x)`