Law of multipole proportions: sulphur forms two chlowides. `A 30.00 h` sample of one electric decomposes to give `5.53 g` fo sulphur `(S)` and `24.47 g` fo chloring `(CI) A 30.00 g` sample of the other chloride decomposes to give `3.93 g` of `S` and `26.07 g` of `CI`. Show that these compounds obey the law of multiple prooportions.
Strategy: First we calculate the mass of `Cl` that combines with `1 g` of `S` in each compound. Then we determine the ratio of the different masses fo `Cl` for the two compounds.

Explanation

In sulphur chloride `I`,
`5.53 g` of `S` combines with `24.47g` of `Cl`
`:. 1g` of `S` combines with `(24.47)/(5.53)g` of `Cl`, i.e., `4.2g` of `Cl`
In sulpur chloride II,
`3.93g` of `S` will combines with `26.07g` of `Cl`
`:. 1g` f `S` will combine with `(26.07)/(3.93)g` of `Cl` the two compounds is
`4.42: 6.63 = (4.42)/(4.42) : (6.63)/(4.42)`
`= 1:1.5`
`= 2:3 larr` Ratio of small whole numbers
Thus, these compounds obey the law of mutilple proportions.