Percent of solute: Calculate the mass of calcium suphate `(CaSO_(4))` contained in `200g` of a `6.00%` solution of `CaSO_(4)`
Strategy: Percent infromation means the solution contains `6.00g` fo `CaSO_(4)` per `100g` of solution. To solve the problem, we can use either unitary method or Eq (1.16) or construct a unit factor.

Explanation

(i) Unitary method:
`100g` solution contains `6.00g CaSO_(4)`
`1g` solution contains `(6.00)/(100)g CaSO_(4)`
`200g` solution contains `(6.00)/(100) xx 200g CaSO_(4)`
`= 12.0g CaSO_(4)`
(ii) Using Eq (1.16)
Percent solute `= ("Mass of solute")/("Mass of solution") xx100%`
`:.` Mass of solute `= (("Percent solute") xx ("Mass of solution"))/(100%)`
`= ((6.00%) (200g))/(100%) = 120g CaSO_(4)`
(iii) Factor-label method
`?g CaSO_(4) = 200g "soln" xx (6.00g CaSO_(4))/(100g "soln".) = 12.0g CaSO_(4)`