What is the equivalent weight of phosphoric acid `(H_(3) PO_(4))` according to the equation
`NaOH + H_(3) PO_(4) rarr NaH_(2) PO_(4) + H_(2)O`

Options

A. `98 u`
B. `59 u`
C. `49 u`
D. `25 u`

Answer

A

Explanation

Equivalent weight
`("Formula weight")/("Number of" H "atoms furnished as protons")`
Accoriding to the above equation. `H_(3) PO_(4)` releases just one `H` atom as proton Thus,
Eq. `wt = (98u)/(1) = 98u`