What is the shortest wavelength (in nanometers) in the Lyman series of the hydrogen spectrum?
Strategy: The Lyman series is given by the Balmer -Rydberg equation with `n = 1` and `mgt 1`. The shortest-wavelength line occurs when `1//m^(2)` is zero or when `m` is infinitely large (i.e., if `m =oo`, then `1//m^(2) = 0)`.

Explanation

According to the Balmer -Rydbergy equation.
`(1)/(lambda) = R ((1)/(1^(2))-(1)/(oo^(2)))`
`= 1.097xx 10^(7)m^(-1) (1-0)`
`= 1.097xx10^(7)m^(-1)`
or `lambda = (1)/(1.097 xx 10^(7)m^(-1)) = 0.9116xx 10^(-7)m = 91.2 nm`