Calculate the enegry of an electron in the first Bohr orbit if a hydrogen atom.
Strategy: Use Eq. to obtain directly the energy of the lowest stationary state (or ground state).

Explanation

Assume `n = 1`, take `Z = 1`, and insert the values of the constants of obtain
`E_(1) =- ((2)(3.14)^(2)(1)^(2)(4.8xx10^(-10)esu)^(4)(9.11xx10^(-18)g))/((1)^(2)(6.63xx10^(-27)erg s)^(2))`
`=- 2.188 xx 10^(-11) "erg atom"^(-1)`
`=- 2.188 xx 10^(-18) J "atom"^(-1)`
`=- 13.6eV "atom"^(-1)`
`=- 1312 kJ mol^(-1)`