Assume that we are travelling at a speed of `90 km h^(-1)` in a small car with a mass of `1250 kg`. If the unceratinty in the velocity of the car is `1%(Deltav = 0.9 km h^(-1))`, what is the uncertainty (in metars) in the position of the car?
Strategy: Heisenberg's uncertainty relasionship states that the uncertainity in an object's position, `Deltax`, times the uncertainty in its momentum, `Deltap_(x)`, is equal to or greater than the quantity `h//pi4`. In the present case, we need to find `Deltax` when `Deltav` is known. We need to convert `Deltav` into `ms^(-1)`).

Explanation

According to Eq.
`DeltaxDeltaV_(x) ge (h)/(4pim)`
Therefore, `Deltax ge (h)/(4pimDeltaV_(x))`
`Deltax ge (6.63xx10^(-34) kg m^(2)s^(-1))/((4)(3.14)(1250kg)(0.9km h^(-1))((1h)/(3600s))((1000m)/(1km)))`
`ge0.00169 xx 10^(-34)m`
`ge 1.69 xx 10^(-37)m`