Avogardo's number is the number of atomic mass units in one

Options

A. gram
B. miligram
C. Kilogram
D. decigarm

Answer

A

Explanation

Let us calculate the mass, in atomic mass units, of `1.000g` of `._(6)^(12)C` atoms.
`a"mu"= 1.000g _(6)^(12)C` atoms `xx (1 mol _(6)^(12)C)/(12 g _(6)^(12)C "atoms")`
`xx(6.022xx10^(23)_(6)^(12)C at om)/(1mol _(6)^(12)C at om)xx(12 am u)/(_(6)^(12)C at om)`
`= 6.022 xx 10^(23)am u (in 1g)`
Thus, `1g = 6.022 xx 10^(23) am u`
`1am u = 1.660 xx 10^(-24)g`
(aproximately the mass of one atom of `._(1)^(1)H`, the lighter isotope of the element with lowest mass).