The angular momentum of the electron moving around the nucleus in a circular orbit of radius `r` is given by
A
`m_(e)vr`
B
`m_(e)v//r`
C
`m_(e)vr^(2)`
D
`m_(e)v//r^(2)`
Text Solution
Verified by Experts
The correct Answer is:
A
Just as linear momentum is the product of mass `(m)` and linear velocity `(V)`, angular momentum is the product of moment of inertia `(I)` and angular velocity `(omega)`. For an electron of mass `m_(e)` moving in a circular orbit of radius `r` around the nucleus, Angular momenutm `= I xx omega` Since `I = m_(e)r^(2)` and `omega = v//r`, where `v` is the linear velocity, Angular momentum `= m_(e)r^(2) xx (v)/(r) = m_(e)vr`
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