The possible values of `l` depend on the value of the principal quantum number `n`. For a given value of `n, l` has possible intergal values from

Options

A. `0`to `n`
B. `1`to`n-1`
C. `1`to`n`
D. `0`to `n-1`

Answer

D

Explanation

If `n = 1`, there is only one possible value of `l`, that is, `l = n - 1=1 - 1 = 0`. If `n = 2`, there are two values of `l`, given by `0`, and `1`. If `n = 3`, there are three values of `l`, given by `0, 1`, and `2`. Thus, the maximum value of `l` is `(n - 1)`