How many peacks are present in the radial distribution function for the `3d` orbital?

Options

A. Zero
B. One
C. Two
D. Three

Explanation

To determine how many peaks are present in the radial distribution function for the 3d orbital, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Principal Quantum Number (n)**:
- For the 3d orbital, the principal quantum number \( n \) is 3.

2. **Determine the Number of Radial Nodes**:
- The formula for the number of radial nodes in an orbital is given by:
\[ \text{Number of radial nodes} = n - l - 1 \]
- For d orbitals, the azimuthal quantum number \( l \) is 2 (since \( l = 0 \) for s, \( l = 1 \) for p, and \( l = 2 \) for d).
- Substituting the values:
\[ \text{Number of radial nodes} = 3 - 2 - 1 = 0 \]

3. **Calculate the Number of Peaks**:
- The number of peaks in the radial distribution function is given by:
\[ \text{Number of peaks} = \text{Number of radial nodes} + 1 \]
- Since we found that the number of radial nodes is 0, we can substitute this into the equation:
\[ \text{Number of peaks} = 0 + 1 = 1 \]

4. **Conclusion**:
- Therefore, the radial distribution function for the 3d orbital has **1 peak**.

### Final Answer:
The number of peaks present in the radial distribution function for the 3d orbital is **1**.